.5[(10+h)(h)]=12

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Solution for .5[(10+h)(h)]=12 equation:


Simplifying
0.5[(10 + h)(h)] = 12

Reorder the terms for easier multiplication:
0.5[h(10 + h)] = 12
0.5[(10 * h + h * h)] = 12
0.5[(10h + h2)] = 12
[10h * 0.5 + h2 * 0.5] = 12
[5h + 0.5h2] = 12

Solving
5h + 0.5h2 = 12

Solving for variable 'h'.

Reorder the terms:
-12 + 5h + 0.5h2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 5h + 0.5h2 = 0

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
-24 + 10h + h2 = 0

Move the constant term to the right:

Add '24' to each side of the equation.
-24 + 10h + 24 + h2 = 0 + 24

Reorder the terms:
-24 + 24 + 10h + h2 = 0 + 24

Combine like terms: -24 + 24 = 0
0 + 10h + h2 = 0 + 24
10h + h2 = 0 + 24

Combine like terms: 0 + 24 = 24
10h + h2 = 24

The h term is 10h.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10h + 25 + h2 = 24 + 25

Reorder the terms:
25 + 10h + h2 = 24 + 25

Combine like terms: 24 + 25 = 49
25 + 10h + h2 = 49

Factor a perfect square on the left side:
(h + 5)(h + 5) = 49

Calculate the square root of the right side: 7

Break this problem into two subproblems by setting 
(h + 5) equal to 7 and -7.

Subproblem 1

h + 5 = 7 Simplifying h + 5 = 7 Reorder the terms: 5 + h = 7 Solving 5 + h = 7 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + h = 7 + -5 Combine like terms: 5 + -5 = 0 0 + h = 7 + -5 h = 7 + -5 Combine like terms: 7 + -5 = 2 h = 2 Simplifying h = 2

Subproblem 2

h + 5 = -7 Simplifying h + 5 = -7 Reorder the terms: 5 + h = -7 Solving 5 + h = -7 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + h = -7 + -5 Combine like terms: 5 + -5 = 0 0 + h = -7 + -5 h = -7 + -5 Combine like terms: -7 + -5 = -12 h = -12 Simplifying h = -12

Solution

The solution to the problem is based on the solutions from the subproblems. h = {2, -12}

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